Due: 21-Jan-2016, 11.55 am
Exercise-1 Exercise-2 Exercise-3 Exercise-4 Exercise-5 Exercise-6 Exercise-7 Exercise-8 Exercise-9 Exercise-10 Exercise-11 Exercise-12
This lab is split into three parts. The first part concentrates on getting familiarized with x86 assembly language, the QEMU x86 emulator, and the PC's power-on bootstrap procedure. The second part examines the boot loader for our kernel, which resides in the boot directory of the lab tree. Finally, the third part delves into the initial template for our kernel itself, named JOS, which resides in the kern directory.
Part-1 and 2 of this lab are meant to understand some of the internals of boot procedure and don't require any coding. But you need to understand the concepts as they can be asked during demo or quizzes. Part-3 involves coding as well.
Once you have completed the steps as listed in the common instructions for cloning the git repository, you don't need to do anything more. This portion of the lab belongs to origin/lab1 branch on the git repository.
On a GCL machine (or add path to palasi if working from individual machine): bash% git clone /home/phd/kedia/os_TA/lab.git Cloning into lab... bash% cd lab bash%
The lab code comes with GNU Make rules to make submission easier. After commiting your final changes to the lab, type make tarball to submit your lab.
bash% git commit -am "ready to submit my lab" [lab1 c2e3c8b] ready to submit my lab 2 files changed, 18 insertions(+), 2 deletions(-) bash% make tarball git archive --prefix=lab1/ --format=tar HEAD | gzip > lab1-handin.tar.gz bash%make tarball will create a tar.gz file of your workspace and you are supposed to upload it on moodle page.
For Lab 1, you do not need to turn in answers to any of the questions below. You just need to implement the code for Exercises mentioned below. (Do answer them for yourself though! They will help with the rest of the lab.)
We will be grading your solutions with a grading program. You can run make grade to test your solutions with the grading program.
We will be using a detailed version of the grading program to check your assignments.
Instead of developing the operating system on a real, physical personal computer (PC), we use a program that faithfully emulates a complete PC: the code you write for the emulator will boot on a real PC too. Using an emulator simplifies debugging; you can, for example, set break points inside of the emulated x86, which is difficult to do with the silicon version of an x86.
In this course we will use the QEMU Emulator, a modern and relatively fast emulator. While QEMU's built-in monitor provides only limited debugging support, QEMU can act as a remote debugging target for the GNU debugger (GDB), which we'll use in this lab to step through the early boot process.
To get started, cd into the lab directory then type make (or gmake on BSD systems) in the lab directory to build the minimal boot loader and kernel you will start with.
bash% cd lab bash% make + as kern/entry.S + cc kern/init.c + cc kern/console.c + cc kern/monitor.c + cc kern/printf.c + cc lib/printfmt.c + cc lib/readline.c + cc lib/string.c + ld obj/kern/kernel + as boot/boot.S + cc -Os boot/main.c + ld boot/boot boot block is 414 bytes (max 510) + mk obj/kern/kernel.img
(If you get errors like "undefined reference to `__udivdi3'", you probably don't have the 32-bit gcc multilib. If you're running Debian or Ubuntu, try installing the gcc-multilib package.)
Now you're ready to run QEMU, supplying the file obj/kern/kernel.img, created above, as the contents of the emulated PC's "virtual hard disk." This hard disk image contains both our boot loader (obj/boot/boot) and our kernel (obj/kernel).
bash% make qemu
This executes QEMU with the options required to set the hard disk and direct serial port output to the terminal. Some text should appear in the QEMU window:
Booting from Hard Disk... 6828 decimal is XXX octal! entering test_backtrace 5 entering test_backtrace 4 entering test_backtrace 3 entering test_backtrace 2 entering test_backtrace 1 entering test_backtrace 0 leaving test_backtrace 0 leaving test_backtrace 1 leaving test_backtrace 2 leaving test_backtrace 3 leaving test_backtrace 4 leaving test_backtrace 5 Welcome to the JOS kernel monitor! Type 'help' for a list of commands. K>
Everything after 'Booting from Hard Disk...' was printed by our skeletal JOS kernel; the K> is the prompt printed by the small monitor, or interactive control program, that we've included in the kernel. After you finish Exercise 7, these lines printed by the kernel will also appear in the regular shell window from which you ran QEMU. The regular shell output will be used for lab grading/testing purposes. More on this in Exercise 7.
There are only two commands you can give to the kernel monitor, help and kerninfo.
K> help help - display this list of commands kerninfo - display information about the kernel K> kerninfo Special kernel symbols: entry f010000c (virt) 0010000c (phys) etext f0101a75 (virt) 00101a75 (phys) edata f0112300 (virt) 00112300 (phys) end f0112960 (virt) 00112960 (phys) Kernel executable memory footprint: 75KB K>
The help command is obvious, and we will shortly discuss the meaning of what the kerninfo command prints. Although simple, it's important to note that this kernel monitor is running "directly" on the "raw (virtual) hardware" of the simulated PC. This means that you should be able to copy the contents of obj/kern/kernel.img onto the first few sectors of a real hard disk, insert that hard disk into a real PC, turn it on, and see exactly the same thing on the PC's real screen as you did above in the QEMU window. (We don't recommend you do this on a real machine with useful information on its hard disk, though, because copying kernel.img onto the beginning of its hard disk will trash the master boot record and the beginning of the first partition, effectively causing everything previously on the hard disk to be lost!)
We will now dive into a bit more detail about how a PC starts up. A PC's physical address space is hard-wired to have the following general layout:
+------------------+ <- 0xFFFFFFFF (4GB) | 32-bit | | memory mapped | | devices | | | /\/\/\/\/\/\/\/\/\/\ /\/\/\/\/\/\/\/\/\/\ | | | Unused | | | +------------------+ <- depends on amount of RAM | | | | | Extended Memory | | | | | +------------------+ <- 0x00100000 (1MB) | BIOS ROM | +------------------+ <- 0x000F0000 (960KB) | 16-bit devices, | | expansion ROMs | +------------------+ <- 0x000C0000 (768KB) | VGA Display | +------------------+ <- 0x000A0000 (640KB) | | | Low Memory | | | +------------------+ <- 0x00000000 |
The first PCs, which were based on the 16-bit Intel 8088 processor, were only capable of addressing 1MB of physical memory. The physical address space of an early PC would therefore start at 0x00000000 but end at 0x000FFFFF instead of 0xFFFFFFFF. The 640KB area marked "Low Memory" was the only random-access memory (RAM) that an early PC could use; in fact the very earliest PCs only could be configured with 16KB, 32KB, or 64KB of RAM!
The 384KB area from 0x000A0000 through 0x000FFFFF was reserved by the hardware for special uses such as video display buffers and firmware held in non-volatile memory. The most important part of this reserved area is the Basic Input/Output System (BIOS), which occupies the 64KB region from 0x000F0000 through 0x000FFFFF. In early PCs the BIOS was held in true read-only memory (ROM), but current PCs store the BIOS in updateable flash memory. The BIOS is responsible for performing basic system initialization such as activating the video card and checking the amount of memory installed. After performing this initialization, the BIOS loads the operating system from some appropriate location such as floppy disk, hard disk, CD-ROM, or the network, and passes control of the machine to the operating system.
When Intel finally "broke the one megabyte barrier" with the 80286 and 80386 processors, which supported 16MB and 4GB physical address spaces respectively, the PC architects nevertheless preserved the original layout for the low 1MB of physical address space in order to ensure backward compatibility with existing software. Modern PCs therefore have a "hole" in physical memory from 0x000A0000 to 0x00100000, dividing RAM into "low" or "conventional memory" (the first 640KB) and "extended memory" (everything else). In addition, some space at the very top of the PC's 32-bit physical address space, above all physical RAM, is now commonly reserved by the BIOS for use by 32-bit PCI devices.
Recent x86 processors can support more than 4GB of physical RAM, so RAM can extend further above 0xFFFFFFFF. In this case the BIOS must arrange to leave a second hole in the system's RAM at the top of the 32-bit addressable region, to leave room for these 32-bit devices to be mapped. Because of design limitations JOS will use only the first 256MB of a PC's physical memory anyway, so for now we will pretend that all PCs have "only" a 32-bit physical address space. But dealing with complicated physical address spaces and other aspects of hardware organization that evolved over many years is one of the important practical challenges of OS development.
In this portion of the lab, you'll use QEMU's debugging facilities to investigate how an IA-32 compatible computer boots.
Open two terminal windows. In one, enter make qemu-gdb. This starts up QEMU, but QEMU stops just before the processor executes the first instruction and waits for a debugging connection from GDB. In the second terminal, from the same directory you ran make, run gdb. You should see something like this,
bash% gdb GNU gdb (GDB) 6.8-debian Copyright (C) 2008 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html> This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. Type "show copying" and "show warranty" for details. This GDB was configured as "i486-linux-gnu". + target remote localhost:26000 The target architecture is assumed to be i8086 [f000:fff0] 0xffff0: ljmp $0xf000,$0xe05b 0x0000fff0 in ?? () + symbol-file obj/kern/kernel (gdb)
We provided a .gdbinit file that set up GDB to debug the 16-bit code used during early boot and directed it to attach to the listening QEMU. (If it doesn't work, you may have to add an add-auto-load-safe-path in your .gdbinit in your home directory to convince gdb to process the .gdbinit we provided. gdb will tell you if you have to do this.)
The following line:
[f000:fff0] 0xffff0: ljmp $0xf000,$0xe05b
is GDB's disassembly of the first instruction to be executed. From this output you can conclude a few things:
Why does QEMU start like this? This is how Intel designed the 8088 processor, which IBM used in their original PC. Because the BIOS in a PC is "hard-wired" to the physical address range 0x000f0000-0x000fffff, this design ensures that the BIOS always gets control of the machine first after power-up or any system restart - which is crucial because on power-up there is no other software anywhere in the machine's RAM that the processor could execute. The QEMU emulator comes with its own BIOS, which it places at this location in the processor's simulated physical address space. On processor reset, the (simulated) processor enters real mode and sets CS to 0xf000 and the IP to 0xfff0, so that execution begins at that (CS:IP) segment address. How does the segmented address 0xf000:fff0 turn into a physical address?
To answer that we need to know a bit about real mode addressing. In real mode (the mode that PC starts off in), address translation works according to the formula: physical address = 16 * segment + offset. So, when the PC sets CS to 0xf000 and IP to 0xfff0, the physical address referenced is:
16 * 0xf000 + 0xfff0 # in hex multiplication by 16 is = 0xf0000 + 0xfff0 # easy--just append a 0. = 0xffff0
0xffff0 is 16 bytes before the end of the BIOS (0x100000). Therefore we shouldn't be surprised that the first thing that the BIOS does is jmp backwards to an earlier location in the BIOS; after all how much could it accomplish in just 16 bytes?
Exercise 1. Use GDB's si (Step Instruction) command to trace into the ROM BIOS for a few more instructions, and try to guess what it might be doing. No need to figure out all the details - just the general idea of what the BIOS is doing first.
When the BIOS runs, it sets up an interrupt descriptor table and initializes various devices such as the VGA display. This is where the "Starting SeaBIOS" message you see in the QEMU window comes from.
After initializing the PCI bus and all the important devices the BIOS knows about, it searches for a bootable device such as a floppy, hard drive, or CD-ROM. Eventually, when it finds a bootable disk, the BIOS reads the boot loader from the disk and transfers control to it.
Floppy and hard disks for PCs are divided into 512 byte regions called sectors. A sector is the disk's minimum transfer granularity: each read or write operation must be one or more sectors in size and aligned on a sector boundary. If the disk is bootable, the first sector is called the boot sector, since this is where the boot loader code resides. When the BIOS finds a bootable floppy or hard disk, it loads the 512-byte boot sector into memory at physical addresses 0x7c00 through 0x7dff, and then uses a jmp instruction to set the CS:IP to 0000:7c00, passing control to the boot loader. Like the BIOS load address, these addresses are fairly arbitrary - but they are fixed and standardized for PCs.
The ability to boot from a CD-ROM came much later during the evolution of the PC, and as a result the PC architects took the opportunity to rethink the boot process slightly. As a result, the way a modern BIOS boots from a CD-ROM is a bit more complicated (and more powerful). CD-ROMs use a sector size of 2048 bytes instead of 512, and the BIOS can load a much larger boot image from the disk into memory (not just one sector) before transferring control to it. For more information, see the "El Torito" Bootable CD-ROM Format Specification.
For this course, however, we will use the conventional hard drive boot mechanism, which means that our boot loader must fit into a measly 512 bytes. The boot loader consists of one assembly language source file, boot/boot.S, and one C source file, boot/main.c Look through these source files carefully and make sure you understand what's going on. The boot loader must perform two main functions:
After you understand the boot loader source code, look at the file obj/boot/boot.asm. This file is a disassembly of the boot loader that our GNUmakefile creates after compiling the boot loader. This disassembly file makes it easy to see exactly where in physical memory all of the boot loader's code resides, and makes it easier to track what's happening while stepping through the boot loader in GDB. Likewise, obj/kern/kernel.asm contains a disassembly of the JOS kernel, which can often be useful for debugging.
You can set address breakpoints in GDB with the b command. For example, b *0x7c00 sets a breakpoint at address 0x7C00. Once at a breakpoint, you can continue execution using the c and si commands: c causes QEMU to continue execution until the next breakpoint (or until you press Ctrl-C in GDB), and si N steps through the instructions N at a time.
To examine instructions in memory (besides the immediate next one to be executed, which GDB prints automatically), you use the x/i command. This command has the syntax x/Ni ADDR, where N is the number of consecutive instructions to disassemble and ADDR is the memory address at which to start disassembling.
Exercise 2. Take a look at the lab tools guide, especially the section on GDB commands. Even if you're familiar with GDB, this includes some esoteric GDB commands that are useful for OS work.
Set a breakpoint at address 0x7c00, which is where the boot sector will be loaded. Continue execution until that breakpoint. Trace through the code in boot/boot.S, using the source code and the disassembly file obj/boot/boot.asm to keep track of where you are. Also use the x/i command in GDB to disassemble sequences of instructions in the boot loader, and compare the original boot loader source code with both the disassembly in obj/boot/boot.asm and GDB.
Trace into bootmain() in boot/main.c, and then into readsect(). Identify the exact assembly instructions that correspond to each of the statements in readsect(). Trace through the rest of readsect() and back out into bootmain(), and identify the begin and end of the for loop that reads the remaining sectors of the kernel from the disk. Find out what code will run when the loop is finished, set a breakpoint there, and continue to that breakpoint. Then step through the remainder of the boot loader.
Be able to answer the following questions:
We will now look in further detail at the C language portion of the boot loader, in boot/main.c. But before doing so, this is a good time to stop and review some of the basics of C programming.
Exercise 3. Read about programming with pointers in C. The best reference for the C language is The C Programming Language by Brian Kernighan and Dennis Ritchie (known as 'K&R').
Read 5.1 (Pointers and Addresses) through 5.5 (Character Pointers and Functions) in K&R. Then download the code for pointers.c, run it, and make sure you understand where all of the printed values come from. In particular, make sure you understand where the pointer addresses in lines 1 and 6 come from, how all the values in lines 2 through 4 get there, and why the values printed in line 5 are seemingly corrupted.
There are other references on pointers in C (e.g., A tutorial by Ted Jensen that cites K&R heavily), though not as strongly recommended.
Warning: Unless you are already thoroughly versed in C, do not skip or even skim this reading exercise. If you do not really understand pointers in C, you will suffer untold pain and misery in subsequent labs, and then eventually come to understand them the hard way.
To make sense out of boot/main.c you'll need to know what an ELF binary is. When you compile and link a C program such as the JOS kernel, the compiler transforms each C source ('.c') file into an object ('.o') file containing assembly language instructions encoded in the binary format expected by the hardware. The linker then combines all of the compiled object files into a single binary image such as obj/kern/kernel, which in this case is a binary in the ELF format, which stands for "Executable and Linkable Format".
Full information about this format is available in the ELF specification but you will not need to delve very deeply into the details of this format in this class. Although as a whole the format is quite powerful and complex, most of the complex parts are for supporting dynamic loading of shared libraries, which we will not do in this class. The Wikipedia page has a short description.
For purposes of this course, you can consider an ELF executable to be a header with loading information, followed by several program sections, each of which is a contiguous chunk of code or data intended to be loaded into memory at a specified address. The boot loader does not modify the code or data; it loads it into memory and starts executing it.
An ELF binary starts with a fixed-length ELF header, followed by a variable-length program header listing each of the program sections to be loaded. The C definitions for these ELF headers are in inc/elf.h. The program sections we're interested in are:
When the linker computes the memory layout of a program, it reserves space for uninitialized global variables, such as int x;, in a section called .bss that immediately follows .data in memory. C requires that "uninitialized" global variables start with a value of zero. Thus there is no need to store contents for .bss in the ELF binary; instead, the linker records just the address and size of the .bss section. The loader or the program itself must arrange to zero the .bss section.
Examine the full list of the names, sizes, and link addresses of all the sections in the kernel executable by typing:
bash% objdump -h obj/kern/kernel
You will see many more sections than the ones we listed above, but the others are not important for our purposes. Most of the others (e.g. stab) are to hold debugging information, which is typically included in the program's executable file but not loaded into memory by the program loader.
Take particular note of the "VMA" (or link address) and the "LMA" (or load address) of the .text section. The load address of a section is the memory address at which that section should be loaded into memory.
The link address of a section is the memory address from which the section expects to execute. The linker encodes the link address in the binary in various ways, such as when the code needs the address of a global variable, with the result that a binary usually won't work if it is executing from an address that it is not linked for. (It is possible to generate position-independent code that does not contain any such absolute addresses. This is used extensively by modern shared libraries, but it has performance and complexity costs, so we won't be using it here.)
Typically, the link and load addresses are the same. For example, look at the .text section of the boot loader:
bash% objdump -h obj/boot/boot.out
The boot loader uses the ELF program headers to decide how to load the sections. The program headers specify which parts of the ELF object to load into memory and the destination address each should occupy. You can inspect the program headers by typing:
bash% objdump -x obj/kern/kernel
The program headers are then listed under "Program Headers" in the output of objdump. The areas of the ELF object that need to be loaded into memory are those that are marked as "LOAD". Other information for each program header is given, such as the virtual address ("vaddr"), the physical address ("paddr"), and the size of the loaded area ("memsz" and "filesz").
Back in boot/main.c, the ph->p_pa
field of each program header
contains the segment's destination physical address (in this case, it really is
a physical address, though the ELF specification is vague on the actual meaning
of this field).
The BIOS loads the boot sector into memory starting at address 0x7c00, so this is the boot sector's load address. This is also where the boot sector executes from, so this is also its link address. We set the link address by passing -Ttext 0x7C00 to the linker in boot/Makefrag, so the linker will produce the correct memory addresses in the generated code.
Exercise 4. Trace through the first few instructions of the boot loader again and identify the first instruction that would "break" or otherwise do the wrong thing if you were to get the boot loader's link address wrong. Then change the link address in boot/Makefrag to something wrong, run make clean, recompile the lab with make, and trace into the boot loader again to see what happens. Don't forget to change the link address back and make clean again afterward!
Look back at the load and link addresses for the kernel. Unlike the boot loader, these two addresses aren't the same: the kernel is telling the boot loader to load it into memory at a low address (1 megabyte), but it expects to execute from a high address. We'll dig in to how we make this work in the next section.
Besides the section information, there is one more field in the ELF header that is important to us, named e_entry. This field holds the link address of the entry point in the program: the memory address in the program's text section at which the program should begin executing. You can see the entry point:
bash% objdump -f obj/kern/kernel
You should now be able to understand the minimal ELF loader in boot/main.c. It reads each section of the kernel from disk into memory at the section's load address and then jumps to the kernel's entry point.
Exercise 5. We can examine memory using GDB's x command. The GDB manual has full details, but for now, it is enough to know that the command x/Nx ADDR prints N words of memory at ADDR. (Note that both 'x's in the command are lowercase.) Warning: The size of a word is not a universal standard. However, in our setup, you may see that a word is four bytes.
Reset the machine (exit QEMU/GDB and start them again). Examine the 8 words of memory at 0x00100000 at the point the BIOS enters the boot loader, and then again at the point the boot loader enters the kernel. Why are they different? What is there at the second breakpoint? (You do not really need to use QEMU to answer this question. Just think.)
We will now start to examine the minimal JOS kernel in a bit more detail. (And you will finally get to write some code!). Like the boot loader, the kernel begins with some assembly language code that sets things up so that C language code can execute properly.
When you inspected the boot loader's link and load addresses above, they matched perfectly, but there was a (rather large) disparity between the kernel's link address (as printed by objdump) and its load address. Go back and check both and make sure you can see what we're talking about. (Linking the kernel is more complicated than the boot loader, so the link and load addresses are at the top of kern/kernel.ld.)
Operating system kernels often like to be linked and run at very high virtual address, such as 0xf0100000, in order to leave the lower part of the processor's virtual address space for user programs to use. The reason for this arrangement will become clearer in the next lab.
Many machines don't have any physical memory at address 0xf0100000, so we can't count on being able to store the kernel there. Instead, we will use the processor's memory management hardware to map virtual address 0xf0100000 (the link address at which the kernel code expects to run) to physical address 0x00100000 (where the boot loader loaded the kernel into physical memory). This way, although the kernel's virtual address is high enough to leave plenty of address space for user processes, it will be loaded in physical memory at the 1MB point in the PC's RAM, just above the BIOS ROM. This approach requires that the PC have at least a few megabytes of physical memory (so that physical address 0x00100000 works), but this is likely to be true of any PC built after about 1990.
In fact, in the next lab, we will map the entire bottom 256MB of the PC's physical address space, from physical addresses 0x00000000 through 0x0fffffff, to virtual addresses 0xf0000000 through 0xffffffff respectively. You should now see why JOS can only use the first 256MB of physical memory.
For now, we'll just map the first 4MB of physical memory, which will
be enough to get us up and running. We do this using the
hand-written, statically-initialized page directory and page table in
kern/entrypgdir.c. For now, you don't have to understand the
details of how this works, just the effect that it accomplishes. Up
until kern/entry.S sets the CR0_PG
flag, memory
references are treated as physical addresses (strictly speaking,
they're linear addresses, but boot/boot.S set up an identity mapping
from linear addresses to physical addresses and we're never going to
change that). Once CR0_PG
is set, memory references are
virtual addresses that get translated by the virtual memory hardware
to physical addresses. entry_pgdir
translates virtual
addresses in the range 0xf0000000 through 0xf0400000 to physical
addresses 0x00000000 through 0x00400000, as well as virtual addresses
0x00000000 through 0x00400000 to physical addresses 0x00000000 through
0x00400000. Any virtual address that is not in one of these two
ranges will cause a hardware exception which, since we haven't set up
interrupt handling yet, will cause QEMU to dump the machine state and
exit.
Exercise 6.
Use QEMU and GDB to trace into the JOS kernel
and stop at the movl %eax, %cr0
. Examine memory
at 0x00100000 and at 0xf0100000. Now, single step over that
instruction using the stepi GDB command. Again,
examine memory at 0x00100000 and at 0xf0100000. Make sure you
understand what just happened.
Most people take functions like printf() for granted, sometimes even thinking of them as "primitives" of the C language. But in an OS kernel, we have to implement all I/O ourselves.
Read through kern/printf.c, lib/printfmt.c, and kern/console.c, and make sure you understand their relationship.
Exercise 7. (Coding) As of now, the text is printed only in the QEMU window, but not in the shell from where QEMU was invoked. We have omitted a small section of code which does this printing. Find out and fill in the section to get the same output printed on the shell as well.
These lines printed by the kernel needs to appear in the regular shell window from which you ran QEMU. This is because for testing and lab grading purposes we have set up the JOS kernel to write its console output not only to the virtual VGA display (as seen in the QEMU window), but also to the simulated PC's virtual serial port, which QEMU in turn outputs to its own standard output. Likewise, the JOS kernel will take input from both the keyboard and the serial port, so you can give it commands in either the VGA display window or the terminal running QEMU. Alternatively, you can use the serial console without the virtual VGA by running make qemu-nox. This may be convenient if you are SSH'd into an bash dialup.
Exercise 8. (Coding) We have omitted a small fragment of code - the code necessary to print octal numbers using patterns of the form "%o". Find and fill in this code fragment.
Be able to answer the following questions:
1 if (crt_pos >= CRT_SIZE) { 2 int i; 3 memcpy(crt_buf, crt_buf + CRT_COLS, (CRT_SIZE - CRT_COLS) * sizeof(uint16_t)); 4 for (i = CRT_SIZE - CRT_COLS; i < CRT_SIZE; i++) 5 crt_buf[i] = 0x0700 | ' '; 6 crt_pos -= CRT_COLS; 7 }
'y='
? (note: the answer is not a specific value.) Why
does this happen?
cprintf("x=%d y=%d", 3);
cprintf
or its
interface so that it would still be possible to pass it a variable
number of arguments?
In the final exercise of this lab, we will explore in more detail the way the C language uses the stack on the x86, and in the process write a useful new kernel monitor function that prints a backtrace of the stack: a list of the saved Instruction Pointer (IP) values from the nested call instructions that led to the current point of execution.
Exercise 9. Determine where the kernel initializes its stack, and exactly where in memory its stack is located. How does the kernel reserve space for its stack? And at which "end" of this reserved area is the stack pointer initialized to point to?
The x86 stack pointer (esp register) points to the lowest location on the stack that is currently in use. Everything below that location in the region reserved for the stack is free. Pushing a value onto the stack involves decreasing the stack pointer and then writing the value to the place the stack pointer points to. Popping a value from the stack involves reading the value the stack pointer points to and then increasing the stack pointer. In 32-bit mode, the stack can only hold 32-bit values, and esp is always divisible by four. Various x86 instructions, such as call, are "hard-wired" to use the stack pointer register.
The ebp (base pointer) register, in contrast, is associated with the stack primarily by software convention. On entry to a C function, the function's prologue code normally saves the previous function's base pointer by pushing it onto the stack, and then copies the current esp value into ebp for the duration of the function. If all the functions in a program obey this convention, then at any given point during the program's execution, it is possible to trace back through the stack by following the chain of saved ebp pointers and determining exactly what nested sequence of function calls caused this particular point in the program to be reached. This capability can be particularly useful, for example, when a particular function causes an assert failure or panic because bad arguments were passed to it, but you aren't sure who passed the bad arguments. A stack backtrace lets you find the offending function.
Exercise 10.
To become familiar with the C calling conventions on the x86,
find the address of the test_backtrace
function
in obj/kern/kernel.asm,
set a breakpoint there,
and examine what happens each time it gets called
after the kernel starts.
How many 32-bit words does each recursive nesting level
of test_backtrace
push on the stack,
and what are those words?
The above exercise should give you the information you need
to implement a stack backtrace function,
which you should call mon_backtrace()
.
A prototype for this function is already waiting for you
in kern/monitor.c.
You can do it entirely in C,
but you may find the read_ebp()
function in inc/x86.h useful.
You'll also have to hook this new function
into the kernel monitor's command list
so that it can be invoked interactively by the user.
The backtrace function should display a listing of function call frames in the following format:
Stack backtrace: ebp f0109e58 eip f0100a62 args 00000001 f0109e80 f0109e98 f0100ed2 00000031 ebp f0109ed8 eip f01000d6 args 00000000 00000000 f0100058 f0109f28 00000061 ...
The first line printed reflects the currently executing function,
namely mon_backtrace
itself,
the second line reflects the function that called mon_backtrace
,
the third line reflects the function that called that one, and so on.
You should print all the outstanding stack frames.
By studying kern/entry.S
you'll find that there is an easy way to tell when to stop.
Within each line, the ebp value indicates the base pointer into the stack used by that function: i.e., the position of the stack pointer just after the function was entered and the function prologue code set up the base pointer. The listed eip value is the function's return instruction pointer: the instruction address to which control will return when the function returns. The return instruction pointer typically points to the instruction after the call instruction (why?). Finally, the five hex values listed after args are the first five arguments to the function in question, which would have been pushed on the stack just before the function was called. If the function was called with fewer than five arguments, of course, then not all five of these values will be useful. (Why can't the backtrace code detect how many arguments there actually are? How could this limitation be fixed?)
Here are a few specific points you read about in K&R Chapter 5 that are worth remembering for the following exercise and for future labs.
int *p = (int*)100
, then
(int)p + 1
and (int)(p + 1)
are different numbers: the first is 101
but
the second is 104
.
When adding an integer to a pointer, as in the second case,
the integer is implicitly multiplied by the size of the object
the pointer points to.p[i]
is defined to be the same as *(p+i)
,
referring to the i'th object in the memory pointed to by p.
The above rule for addition helps this definition work
when the objects are larger than one byte.&p[i]
is the same as (p+i)
, yielding
the address of the i'th object in the memory pointed to by p.Although most C programs never need to cast between pointers and integers, operating systems frequently do. Whenever you see an addition involving a memory address, ask yourself whether it is an integer addition or pointer addition and make sure the value being added is appropriately multiplied or not.
Exercise 11. (Coding) Implement the backtrace function as specified above. Use the same format as in the example, since otherwise the grading script will be confused. When you think you have it working right, run make grade to see if its output conforms to what our grading script expects, and fix it if it doesn't. After you have handed in your Lab 1 code, you are welcome to change the output format of the backtrace function any way you like.
If you use read_ebp()
, note that GCC may generate
"optimized" code that calls read_ebp()
before
mon_backtrace()
's function prologue, which results in an
incomplete stack trace (the stack frame of the most recent function
call is missing). While we have tried to disable optimizations that
cause this reordering, you may want to examine the assembly of
mon_backtrace()
and make sure the call to
read_ebp()
is happening after the function prologue.
At this point, your backtrace function should give you the addresses of
the function callers on the stack that lead to mon_backtrace()
being executed. However, in practice you often want to know the function
names corresponding to those addresses. For instance, you may want to know
which functions could contain a bug that's causing your kernel to crash.
To help you implement this functionality, we have provided the function
debuginfo_eip()
, which looks up eip in the symbol table
and returns the debugging information for that address. This function is
defined in kern/kdebug.c.
Exercise 12. (Coding) Modify your stack backtrace function to display, for each eip, the function name, source file name, and line number corresponding to that eip.
Complete the implementation of debuginfo_eip
by
inserting the call to stab_binsearch
to find the line
number for an address.
Add a backtrace command to the kernel monitor, and
extend your implementation of mon_backtrace
to
call debuginfo_eip
and print a line for each
stack frame of the form:
K> backtrace Stack backtrace: current eip=f0100a0a kern/monitor.c:101: mon_backtrace+15 ebp f010ff48 eip f0100986 args 00000001 f010ff60 00000000 00000000 f0112560 kern/monitor.c:152: runcmd+230 ebp f010ffb8 eip f01009e9 args f0101e42 00000005 00000000 00010094 00010094 kern/monitor.c:170: monitor+57 ebp f010ffd8 eip f01000f6 args 00000000 00001aac 00000664 00000000 00000000 kern/init.c:43: i386_init+89 ebp f010fff8 eip f010003e args 00111021 00000000 00000000 00000000 00000000
Each line gives the file name and line within that file of the stack frame's eip, followed by the name of the function and the offset of the eip from the first instruction of the function (e.g., monitor+106 means the return eip is 106 bytes past the beginning of monitor).
Be sure to print the file and function names on a separate line, to avoid confusing the grading script.
Tip: printf format strings provide an easy, albeit obscure,
way to print non-null-terminated strings like those in STABS
tables. printf("%.*s", length, string)
prints at
most length
characters of string
.
You may find that some functions are missing from the
backtrace. For example, you will probably see a call to
monitor()
but not to runcmd()
. This is
because the compiler in-lines some function calls.
Other optimizations may cause you to see unexpected line
numbers.
This completes the lab. Please follow the submission checklist on lab page and submit your assignment.